The internal energy of a gas obeying van der Waals equation $(p + \frac{a}{v^{2}})(v-b) = RT$

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asked Jan 13, 2018 in TD by chandu (215k points)

The internal energy of a gas obeying van der Waals equation $(p + \frac{a}{v^{2}})(v-b) = RT$ depends on its

(a) Temperature

(b) Temperature and pressure

(c) Temperature and specific volume

(d) Pressure and specific volume

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first-law-heat&work-energy

The internal energy of a gas obeying van der Waals equation $(p + \frac{a}{v^{2}})(v-b) = RT$

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