Taking g as the acceleration due to gravity, what is the critical depth?

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asked Jan 13, 2018 in FM by chandu (215k points)
edited Aug 27, 2018 by chandu

An open channel of symmetric right angled triangular cross- section is conveying a discharge Q. Taking g as the acceleration due to gravity, what is the critical depth?

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open-channel-flow

Taking g as the acceleration due to gravity, what is the critical depth?

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