The local acceleration (in m/s2) at x = 0 will be

Question

The area of a 2m long tapered duct decreases as A = (0.5 – 0.2x) where ‘x’ is the distance in meters. At a given instant a discharge of 0.5m³/s is flowing in the  duct and is found to increase at a rate of 0.2m³/s. The local acceleration (in m/s²) at x = 0 will be               

(a) 1.4              (b) 1.0             

(c) 0.4              (d) 0.667