A simply supported beam carrying a concentrated load W at mid – span deflects $\delta _{1}$ under the load. If the same beam carries the load W such that it is distributed uniformly over entire length and undergoes a deflection $\delta _{2}$ at the mid span. The ratio $\frac{\delta _{1}}{\delta _{2}}$ is
(a) 2 : 1 (b)$\sqrt{2}$:$1$
(c) 1 : 1 (d) 1 : 2