0 votes
212 views
asked in TOM by (215k points)
edited by
  1. In the figure, link 2 rotates with constant angular velocity $\omega 2$. A slider link 3 moves outwards with a constant relative velocity/P, where Q is point on slider 3 and p is a point on link 2. The magnitude and direction of Coriolis component of acceleration is given by

 

      (a) 2ω2 VQ/P, direction of VQ/P rotated by 900 in the direction ω2

      (b) ω2, VQ/P, direction of VQ/P rotated by 900 in the direction of ω2

      (c) 2ω2, VQ/P, direction of ωV/P rotated by 900 opposite to the direction of ω2

     (d) ω2 VQ/P direction of VQ/P direction of VQ/P direction of VQ/P rotated by 900 Opposite to the direction of ω2

Please log in or register to answer this question.

Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

15.3k users

...