0 votes
69 views
asked in HT by (215k points)

In an oil cooler the oil enters 10 mm diameter tubes at 160°C and is cooled to 40°C. The mean velocity of oil in the tubes is 1.5 m/s. Calculate the mean heat transfer coefficient. For turbulent flow of liquid being cooled take Nu=0.0265 Re0.8Pr0.3 and for laminar flow Nu = 3.65. Take all properties at bulk mean temperature and the properties are listed below:

t

°C

r

kg/m3

v

centi stokes

k

W/m K

c

kJ/kg K

40

878

251.0

0.144

1.96

100

839

20.4

0.137

2.22

160

806

5.7

0.131

2.48

1 centi stoke = 10–6 m2/s        

Please log in or register to answer this question.

Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

15.3k users

...