0 votes
43 views
asked in Thermal by (215k points)

A refrigeration system is to be designed for a cooling capacity of 7.5 tons of refrigeration at saturation pressure corresponding to –200C. It uses refrigerant R-22. Condenser pressure is to be corresponding to saturation temperature of 400C. The refrigeration system uses a liquid-vapour regenerative heat exchanger. The refrigerant vapours coming out of the evaporator are superheated by 50C and then pass through the regenerative heat exchanger to cool the liquid refrigerant coming from the condenser. The temperature of the refrigerant vapours at the exit of heat exchanger is 200 C. The liquid refrigerant is subcooled to 360C at the exit of the condenser. Make a sketch of the system and represent it on P-h and T-S diagrams.The system uses two single-acting cylinders with bore to stroke ratio of 0.8, speed of compressor is 1420 rpm, clearance factor for compressors is 0.04 and polytropic index of compression is 1.1 Mechanical efficiency of the compressor is 0.8.  Determine:

(i)     temperature of liquid refrigerant at the exit of regenerative heat exchanger, assuming specific heat of the liquid to be 1.37 kJ/kg K.

(ii)    mass flow rate of the refrigerant.

(iii)   the temperature of the refrigerant vapours at the exit of compressor, assuming ideal gas behaviour in the superheat region, specific heat of refrigerant vapours in the superheat region may be taken as 0.85 kJ/kg K.

(iv)   Power input to the compressor.

(v)    COP of the system.

(vi)   Volumetric efficiency of the compressor, and

(vii)  Bore and stroke of the compressor.

The following properties of R - 22 are given:

Sat. temp

ts(°C)

Sat pressure

Ps (bar)

 

Sp. Vol. of

Sat. vapour

 (m3 / kg)

Enthalpy (kJ/kg)

 

 

 

 

Sat. Liquid

hf

Sat. vapour

hg

–20

2.448

15.335

177.4

397.5

40

15.335

0.0151

249.08

415.95

         For superheated refrigerant vapour at 2.448 bar and saturation temperature of –200C

Temperature

0C

 

Specific volume

(m3 / kg)

 

Enthalpy

kJ / kg

 

–15

0.0951

400.7

20

0.1107

423.9

 

                                           (ESE-ME-11) (20 M)

 

Please log in or register to answer this question.

Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

15.3k users

...