For steady, fully developed flow inside a straight pipe of diameter D, neglecting gravity effects, the pressure drop $\triangle$p over A length L and the wall shear stress $\tau _{w}$ are related by
(a) $\tau _{w}=\frac{\triangle pD}{4L}$ (b)$\tau _{w}=\frac{4\triangle pD^{2}}{4L^{2}}$
(c)$\tau _{w}=\frac{\triangle pD}{2L}$ (d) $\tau _{w}=\frac{4\triangle pL}{D}$