0 votes
78 views
asked in Engg Maths by (215k points)

The value of the integral $\int_{0}^{2\pi}\left ( \frac{2}{9sin^2\theta} \right )d\theta$ is

  1. $\frac{2\pi}{\sqrt{10}}$
  2. $2\sqrt{10}\pi$
  3. $\sqrt{10}\pi$
  4. $2\pi$

Please log in or register to answer this question.

Related questions

0 votes
0 answers
asked Aug 22, 2017 in Engg Maths by chandu (215k points)
0 votes
0 answers
0 votes
0 answers
asked Aug 29, 2017 in Engg Maths by chandu (215k points)
0 votes
0 answers
asked Aug 22, 2017 in Engg Maths by chandu (215k points)
Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

15.3k users

...