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 A composite wall consist of two layers of different materials having conductivities k1 and k2. For equal thickness of the two layers, the equivalent thermal conductivity of the slab will be                         (IES-97)

($k_1+k_2$                $k_1*k_2$

(c)$2\frac{k_1k_2}{k_1+k_2}$   (d)$\frac{k_1+k_2}{k_1k_2}$

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