0 votes
82 views
asked in PPE by (215k points)
The stagnation temperature of an isentropic flow of air (k=1.4) is 400 K. if the temperature is 200K at a section, then the Mach number of the flow will be

(a) 1.046                      (b) 1.264

(c) 2.236                      (d) 3.211

Please log in or register to answer this question.

Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

15.3k users

...