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A disc of radius’ r ‘has a hole of radius ‘r/2’ cut-out as shown.The centroid of the remaining disc
(shaded portion) at a radial distance from the centre “O” is

(a)$\frac{r}{2}$                                         (b)$\frac{r}{3}$
(c) $\frac{r}{6}$                                         (d)$\frac{r}{8}$

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asked Aug 19, 2017 in SOM by chandu (215k points)
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