0 votes
48 views
asked in tom by (215k points)
An electric lift is moving downwards with a acceleration of $\frac{g}{3}$ . The vertical force between a passenger in the lift and its floor equal to                    

         (a) $\frac{2}{3}$ of the passenger’s weight

         (b)$\frac{3}{4}$  of the passenger’s weight

         (c) passenger’s weight

         (d) $\frac{4}{3}$ of the passenger’s weight

Please log in or register to answer this question.

Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

14.6k users

...