0 votes
90 views
asked in production by (215k points)

A cutting tool is designated in ‘Orthogonal Rake System’ as:

00 – 00 – 60 – 60 – 250 – 750 – 0.8mm

The following data were given

S0 = feed = 0.2 mm/rev

T = depth of cut = 2.0 mm

Vf = chip velocity = 52.6 m/min

ts = dynamic yield shear strength = 400 MPa

Pz = main cutting force= S0 t τs  (ξ sec Ɣ - tan Ɣ + 1)

Where ξ = chip reduction coefficient and

Ɣ  = orthogonal rake

The main cutting force (Pz) and cutting power assuming orthogonal machining are

Please log in or register to answer this question.

Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

14.6k users

...