0 votes
283 views
asked in fm&turbo by (215k points)
edited by

Statement for Linked Answer Q1& Q2

The gap between a moving circular plate and a stationary surface is being continuously reduced, as the circular plate comes down at a uniform speed V towards the stationary bottom surface, as shown in the figure. in the process, the fluid contained between the two plates flows out radially. The fluid is assumed to be incompressible and inviscid.

  1. The radial velocity Vr, at any radius r, when the gap width is h, is

      (a) $V_{r}=\frac{Vr}{2h}$                                                          (b)$V_{r}=\frac{Vr}{h}$

      (c)$V_{r}=\frac{2Vh}{r}$                                                         (d) $V_{r}=\frac{Vh}{r}$ 

 

     2 . The radial component of the fluid acceleration at r = R is

      (a) $\frac{3V^{2}R}{4h^{2}}$                                                               (b)$\frac{V^{2}R}{4h^{2}}$

      (c) $\frac{V^{2}R}{2h^{2}}$                                                               (d) $\frac{V^{2}R}{2r^{2}}$

Please log in or register to answer this question.

Welcome to Q&A discussion forum, where you can ask questions and receive answers from other members of the community.

10.4k questions

274 answers

26 comments

14.6k users

...