Question

A cyclic heat engine does 50 kJ of work pr cycle. If the efficiency of the heat engine is 75%, then hat rejected per cycle is                                                                                                                                                      

      (a) $16\frac{2}{3}KJ$                                                              (b) 33$\frac{1}{3}KJ$ 

      (c) 37$\frac{1}{2}KJ$                                                             (d)$66\frac{2}{3}KJ$