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A truss consists of horizontal members and vertical members having length L each. The members AE, DE and BF are inclined at 450 to the horizontal. For the uniformly distributed load P per unit length on the member EF of the truss shown in the figure, the force in the member CD is              

 

      (a) $\frac{PL}{2}$                   (b) PL

      (c) zero                                        (d) $\frac{2PL}{3}$

1 Answer

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answered by (215k points)
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Method - II

By using section method

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