A truss consists of horizontal members and vertical members having length L each. The members AE, DE and BF are inclined at 450 to the horizontal. For the uniformly distributed load P per unit length on the member EF of the truss shown in the figure, the force in the member CD is
(a) $\frac{PL}{2}$ (b) PL
(c) zero (d) $\frac{2PL}{3}$